The 1976 Federation Cup was the 14th edition of the most important competition between national teams in women's tennis. For the first time, enough teams entered to necessitate pre-qualifying rounds. The tiebreaker also was used for the first time. The tournament was held at The Spectrum in Philadelphia, United States, from 22 to 29 August. The United States defeated Australia in the final, in what was the sixth final between United States and Australia.
Qualifying round Eight nations played off in July for a place in the main draw. Venue (surface)Home teamScoreVisiting teamAustria (Indoor carpet) 0–3 Mexico (Indoor carpet) 3–0 Taiwan (Indoor carpet) 0–3 0–3 Luxembourg, Mexico, Philippines, and Switzerland advanced to Main Draw.
Main draw Participating Teams All ties were played at The Spectrum in Philadelphia, United States, on indoor carpet courts.|}
1st Round losing teams play in Consolation Rounds
First round Indonesia vs. Switzerland
Norway vs. Yugoslavia
Israel vs. United States
New Zealand vs. Argentina
Brazil vs. Netherlands
Denmark vs. Spain
France vs. Great Britain
Hungary vs. Philippines
Sweden vs. Japan
South Korea vs. South Africa
Italy vs. Luxembourg
Mexico vs. West Germany
Belgium vs. Rhodesia
Romania vs. Australia
Second round Canada vs. Switzerland
Yugoslavia vs. United States
Argentina vs. Netherlands
Denmark vs. Uruguay
Sweden vs. South Africa
Italy vs. West Germany
Belgium vs. Australia
Quarterfinals Switzerland vs. United States
Netherlands vs. Denmark
Great Britain vs. South Africa
West Germany vs. Australia
Semifinals United States vs. Netherlands
Great Britain vs. Australia
Final United States vs. Australia
Consolation Rounds Draw
First round Brazil vs. Luxembourg
Japan vs. Israel
South Korea vs. Mexico
Indonesia vs. New Zealand
Norway vs. Spain
Quarterfinals France vs. Rhodesia
Brazil vs. Japan
South Korea vs. New Zealand
Spain vs. Romania
Semifinals France vs. Brazil
South Korea vs. Romania
Final France vs. Romania
References